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0=30t-4.9t^2
We move all terms to the left:
0-(30t-4.9t^2)=0
We add all the numbers together, and all the variables
-(30t-4.9t^2)=0
We get rid of parentheses
4.9t^2-30t=0
a = 4.9; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·4.9·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*4.9}=\frac{0}{9.8} =0 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*4.9}=\frac{60}{9.8} =6+1/8.16666666667 $
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